Solutions Page

Algebra Exercise  :  Q.1 to Q.6 ,  Q.5 and Q.7  ,   Q.8 to Q.14  , Q.15 to Q.18  ,  Q.19 to Q. 21

Answer 5.

(a).     As the base is same

ets-2-6

ets-2-7

ets-2-8

ets-2-9

Answer 7.

ets-2-10

(b).   First make one of the variable equal for both equations

3x – y  = – 5                     x 2(multiply by 2)

x + 2y  = 3                       x 1(multiply by 1)

ets-2-12

Now put this value in equation 2

-1 +2y = 3

2y = 3 + 1

2y = 4

y =  4/2

y = 2

So, x = -1 and y = 2

( c ).    Bring like terms together

15x + 3x -2y – y =18

18x – 3y = 18

Dividing both side by 3 we can reduce the equation to,

6x – y  = 6       ……..Equation 1

10x – 4x + 7y  = 2 – 20

6x  + 7y  = -18                  …………Equation 2

Now one variable ‘x’ is same in both the equation ,

Subtract the equations

ets-2-13

Now put this value in equation 1 ;   6x – ( – 3) = 6

6x + 3 = 6

6x = 3

x = 3/6

x = ½

So,   x  =  ½  and y = -3

                                                                                           NEXT PAGE >>>>>>>

error: